What is the integral from 1 to 4 of |x^2-3x+2| ?

The integral from 1 to 4 of |x^2-3x+2| is 29/6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 1 to 4 of |x^2-3x+2|

\int_{1}^{4} x^{2} - 3 x + 2 d x

\frac{29}{6}

Decimal

4.83333 \dots

Solution steps

\int_{1}^{4} x^{2} - 3 x + 2 d x

Eliminate Absolutes

= \int_{1}^{2} - x^{2} + 3 x - 2 d x + \int_{2}^{4} x^{2} - 3 x + 2 d x

\int_{1}^{2} - x^{2} + 3 x - 2 d x = \frac{1}{6}

\int_{2}^{4} x^{2} - 3 x + 2 d x = \frac{14}{3}

= \frac{1}{6} + \frac{14}{3}

Simplify

\frac{1}{6} + \frac{14}{3} : \frac{29}{6}

= \frac{29}{6}

\int_{0}^{6} \frac{( 36 - x ^{2} )}{144} d x

\int_{2}^{3} \frac{x}{1 + x} d x

\int_{0}^{4} sin (x^{2}) d x

\int_{0}^{1} 10 0^{x} d x

\int_{0}^{1} e^{3 + 3 y} - e^{3 y} d y

What is the integral from 1 to 4 of |x^2-3x+2| ?
The integral from 1 to 4 of |x^2-3x+2| is 29/6