What is the integral from 4 to 8 of 1/(sqrt(x-4)) ?

The integral from 4 to 8 of 1/(sqrt(x-4)) is 4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 4 to 8 of 1/(sqrt(x-4))

\int_{4}^{8} \frac{1}{x - 4} d x

4

Solution steps

\int_{4}^{8} \frac{1}{x - 4} d x

Apply u-substitution

: \int_{0}^{2} 2 d u

= \int_{0}^{2} 2 d u

Integral of a constant:

\int a d x = a x

= [2 u]_{0}^{2}

Compute the boundaries:

4

= 4

\int_{0}^{1} 4 x + 1 d x

\int_{1}^{2} \frac{2 x}{( x ^{2} + 1 ) ^{3}} d x

\int_{4}^{25} \frac{1}{x} d x

\int_{- 3}^{3} \frac{x y ^{2}}{x ^{2} + 1} d y

\int_{2}^{7} ln (x) d x

What is the integral from 4 to 8 of 1/(sqrt(x-4)) ?
The integral from 4 to 8 of 1/(sqrt(x-4)) is 4