What is the integral from 1 to 2 of (3x^2-1)/(x^2) ?

The integral from 1 to 2 of (3x^2-1)/(x^2) is 5/2

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integral from 1 to 2 of (3x^2-1)/(x^2)

\int_{1}^{2} \frac{3 x ^{2} - 1}{x ^{2}} d x

\frac{5}{2}

Decimal

2.5

Solution steps

\int_{1}^{2} \frac{3 x ^{2} - 1}{x ^{2}} d x

Expand

\frac{3 x ^{2} - 1}{x ^{2}} : 3 - \frac{1}{x ^{2}}

= \int_{1}^{2} 3 - \frac{1}{x ^{2}} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{2} 3 d x - \int_{1}^{2} \frac{1}{x ^{2}} d x

\int_{1}^{2} 3 d x = 3

\int_{1}^{2} \frac{1}{x ^{2}} d x = \frac{1}{2}

= 3 - \frac{1}{2}

Simplify

3 - \frac{1}{2} : \frac{5}{2}

= \frac{5}{2}

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What is the integral from 1 to 2 of (3x^2-1)/(x^2) ?
The integral from 1 to 2 of (3x^2-1)/(x^2) is 5/2