What is the integral from 0 to pi of sin(x)-2 ?

The integral from 0 to pi of sin(x)-2 is 2-2pi

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integral from 0 to pi of sin(x)-2

\int_{0}^{π} sin (x) - 2 d x

2 - 2 π

Decimal

- 4.28318 \dots

Solution steps

\int_{0}^{π} sin (x) - 2 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{π} sin (x) d x - \int_{0}^{π} 2 d x

\int_{0}^{π} sin (x) d x = 2

\int_{0}^{π} 2 d x = 2 π

= 2 - 2 π

\int_{- 1}^{2} \frac{e ^{x}}{1 - e ^{x}} d x

\int_{0}^{π} (10 + x) cos (n x) d x

\int_{4}^{x} \frac{1}{1 + t ^{2}} d t

\int_{0}^{π} y sin (x y) d y

\int_{0}^{1} x^{4} - x^{2} d x

What is the integral from 0 to pi of sin(x)-2 ?
The integral from 0 to pi of sin(x)-2 is 2-2pi