What is the integral from 0 to 1 of-x^3 ?

The integral from 0 to 1 of-x^3 is -1/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to 1 of-x^3

\int_{0}^{1} - x^{3} d x

- \frac{1}{4}

Decimal

- 0.25

Solution steps

\int_{0}^{1} - x^{3} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \int_{0}^{1} x^{3} d x

Apply the Power Rule

: [\frac{x ^{4}}{4}]_{0}^{1}

= - [\frac{x ^{4}}{4}]_{0}^{1}

Compute the boundaries:

\frac{1}{4}

= - \frac{1}{4}

\int_{- 2}^{- 1} 1 d x

\int_{- 4}^{4} ∣ x - 2 ∣ d x

\int_{- 2}^{1} - x + 2 - x^{2} d x

\int_{0}^{5} (x - 3) (x - 1) d x

\int_{- 2}^{2} 2 - ∣ x ∣ d x

What is the integral from 0 to 1 of-x^3 ?
The integral from 0 to 1 of-x^3 is -1/4