What is the integral from-pi/2 to pi/2 of 4cos^2(x) ?

The integral from-pi/2 to pi/2 of 4cos^2(x) is 2pi

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integral from-pi/2 to pi/2 of 4cos^2(x)

\int_{- \frac{π}{2}}^{\frac{π}{2}} 4 cos^{2} (x) d x

2 π

Decimal

6.28318 \dots

Solution steps

\int_{- \frac{π}{2}}^{\frac{π}{2}} 4 cos^{2} (x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 4 \cdot \int_{- \frac{π}{2}}^{\frac{π}{2}} cos^{2} (x) d x

Rewrite using trig identities

= 4 \cdot \int_{- \frac{π}{2}}^{\frac{π}{2}} \frac{1 + cos ( 2 x )}{2} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 4 \cdot \frac{1}{2} \cdot \int_{- \frac{π}{2}}^{\frac{π}{2}} 1 + cos (2 x) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= 4 \cdot \frac{1}{2} (\int_{- \frac{π}{2}}^{\frac{π}{2}} 1 d x + \int_{- \frac{π}{2}}^{\frac{π}{2}} cos (2 x) d x)

\int_{- \frac{π}{2}}^{\frac{π}{2}} 1 d x = π

\int_{- \frac{π}{2}}^{\frac{π}{2}} cos (2 x) d x = 0

= 4 \cdot \frac{1}{2} (π + 0)

Simplify

4 \cdot \frac{1}{2} (π + 0) : 2 π

= 2 π

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What is the integral from-pi/2 to pi/2 of 4cos^2(x) ?
The integral from-pi/2 to pi/2 of 4cos^2(x) is 2pi