What is the integral from 5 to 6 of 1/x ?

The integral from 5 to 6 of 1/x is ln(6)-ln(5)

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integral from 5 to 6 of 1/x

\int_{5}^{6} \frac{1}{x} d x

ln (6) - ln (5)

Decimal

0.18232 \dots

Solution steps

\int_{5}^{6} \frac{1}{x} d x

Use the common integral:

\int \frac{1}{x} d x = ln (∣ x ∣)

= [ln ∣ x ∣]_{5}^{6}

Compute the boundaries:

ln (6) - ln (5)

= ln (6) - ln (5)

\int_{0}^{1} θ^{2} + 1 d θ

\int_{0}^{2} 1 - x d x

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\int_{- \infty}^{0} x^{2} e^{2 x} d x

\int_{- a}^{a} \frac{a}{π ( x ^{2} + a ^{2} )} d x

What is the integral from 5 to 6 of 1/x ?
The integral from 5 to 6 of 1/x is ln(6)-ln(5)