What is the integral from 1 to 2 of \sqrt[3]{x} ?

The integral from 1 to 2 of \sqrt[3]{x} is 3/(2^{2/3)}-3/4

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integral from 1 to 2 of \sqrt[3]{x}

\int_{1}^{2} 3 x d x

\frac{3}{2 ^{\frac{2}{3}}} - \frac{3}{4}

Decimal

1.13988 \dots

Solution steps

\int_{1}^{2} 3 x d x

Apply the Power Rule

: [\frac{3}{4} x^{\frac{4}{3}}]_{1}^{2}

= [\frac{3}{4} x^{\frac{4}{3}}]_{1}^{2}

Compute the boundaries:

\frac{3}{2 ^{\frac{2}{3}}} - \frac{3}{4}

= \frac{3}{2 ^{\frac{2}{3}}} - \frac{3}{4}

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What is the integral from 1 to 2 of \sqrt[3]{x} ?
The integral from 1 to 2 of \sqrt[3]{x} is 3/(2^{2/3)}-3/4