What is the integral from 0 to 2 of cos^2(x) ?

The integral from 0 to 2 of cos^2(x) is 1+1/4 sin(4)

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integral from 0 to 2 of cos^2(x)

\int_{0}^{2} cos^{2} (x) d x

1 + \frac{1}{4} sin (4)

Decimal

0.81079 \dots

Solution steps

\int_{0}^{2} cos^{2} (x) d x

Rewrite using trig identities

= \int_{0}^{2} \frac{1 + cos ( 2 x )}{2} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int_{0}^{2} 1 + cos (2 x) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \frac{1}{2} (\int_{0}^{2} 1 d x + \int_{0}^{2} cos (2 x) d x)

\int_{0}^{2} 1 d x = 2

\int_{0}^{2} cos (2 x) d x = \frac{1}{2} sin (4)

= \frac{1}{2} (2 + \frac{1}{2} sin (4))

Simplify

\frac{1}{2} (2 + \frac{1}{2} sin (4)) : 1 + \frac{1}{4} sin (4)

= 1 + \frac{1}{4} sin (4)

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What is the integral from 0 to 2 of cos^2(x) ?
The integral from 0 to 2 of cos^2(x) is 1+1/4 sin(4)