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Popular >

integral from 0 to 8 of 16x-128

Solution

\int_{0}^{8} 16 x - 128 d x

Solution

- 512

Solution steps

\int_{0}^{8} 16 x - 128 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{8} 16 x d x - \int_{0}^{8} 128 d x

\int_{0}^{8} 16 x d x = 512

\int_{0}^{8} 128 d x = 1024

= 512 - 1024

Simplify

= - 512

Graph

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Frequently Asked Questions (FAQ)

What is the integral from 0 to 8 of 16x-128 ?
The integral from 0 to 8 of 16x-128 is -512