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Popular >

integral from 0 to 2 of x^4-8x

Solution

\int_{0}^{2} x^{4} - 8 x d x

Solution

- \frac{48}{5}

+1

Decimal

- 9.6

Solution steps

\int_{0}^{2} x^{4} - 8 x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{2} x^{4} d x - \int_{0}^{2} 8 x d x

\int_{0}^{2} x^{4} d x = \frac{32}{5}

\int_{0}^{2} 8 x d x = 16

= \frac{32}{5} - 16

Simplify

\frac{32}{5} - 16 : - \frac{48}{5}

= - \frac{48}{5}

Graph

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Frequently Asked Questions (FAQ)

What is the integral from 0 to 2 of x^4-8x ?
The integral from 0 to 2 of x^4-8x is -48/5