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Popular >

integral from 0 to 5 of-x^2+9

Solution

\int_{0}^{5} - x^{2} + 9 d x

Solution

\frac{10}{3}

+1

Solution steps

\int_{0}^{5} - x^{2} + 9 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int_{0}^{5} x^{2} d x + \int_{0}^{5} 9 d x

\int_{0}^{5} x^{2} d x = \frac{125}{3}

\int_{0}^{5} 9 d x = 45

= - \frac{125}{3} + 45

Simplify

- \frac{125}{3} + 45 : \frac{10}{3}

= \frac{10}{3}

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\int_{0}^{b} \frac{1}{32} v e^{- \frac{v ^{2}}{64}} d v

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\int_{0.25}^{4} \frac{1}{x} d x

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\int_{1}^{2} 4^{5 x} d x

integral from-5 to 0 of 2(t+1)^{1/3}

\int_{- 5}^{0} 2 (t + 1)^{\frac{1}{3}} d t

integral from 0 to 1.7 of \sqrt[3]{3x+4}

Frequently Asked Questions (FAQ)

What is the integral from 0 to 5 of-x^2+9 ?
The integral from 0 to 5 of-x^2+9 is 10/3