integral from-1 to 1 of (x^2+x+2)

Lösung

\int_{- 1}^{1} (x^{2} + x + 2) d x

\frac{14}{3}

Schritte zur Lösung

\int_{- 1}^{1} x^{2} + x + 2 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{1} x^{2} d x + \int_{- 1}^{1} x d x + \int_{- 1}^{1} 2 d x

\int_{- 1}^{1} x^{2} d x = \frac{2}{3}

\int_{- 1}^{1} x d x = 0

\int_{- 1}^{1} 2 d x = 4

= \frac{2}{3} + 0 + 4

Vereinfache

\frac{2}{3} + 0 + 4 : \frac{14}{3}

= \frac{14}{3}

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