What is the integral from 1 to b of 1/x ?

The integral from 1 to b of 1/x is ln|b|

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 1 to b of 1/x

\int_{1}^{b} \frac{1}{x} d x

ln ∣ b ∣

Solution steps

\int_{1}^{b} \frac{1}{x} d x

Use the common integral:

\int \frac{1}{x} d x = ln (∣ x ∣)

= [ln ∣ x ∣]_{1}^{b}

Compute the boundaries:

ln ∣ b ∣

= ln ∣ b ∣

\int_{1}^{e} \frac{1}{x ( 1 + ln ( x ^{2} ) )} d x

\int_{- 7}^{7} (4 x - 3) d x

\int_{0}^{100} x^{2} d x

\int_{0}^{\frac{π}{4}} 8 sec^{2} (t) d t

\int_{0}^{l n (4 x)} sin (6 e^{t}) d t

What is the integral from 1 to b of 1/x ?
The integral from 1 to b of 1/x is ln|b|