What is the integral from-1 to 1 of sqrt(x) ?

The integral from-1 to 1 of sqrt(x) is 2/3+i 2/3

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integral from-1 to 1 of sqrt(x)

\int_{- 1}^{1} x d x

\frac{2}{3} + i \frac{2}{3}

Solution steps

\int_{- 1}^{1} x d x

Apply the Power Rule

: [\frac{2}{3} x^{\frac{3}{2}}]_{- 1}^{1}

= [\frac{2}{3} x^{\frac{3}{2}}]_{- 1}^{1}

Compute the boundaries:

\frac{2}{3} + i \frac{2}{3}

= \frac{2}{3} + i \frac{2}{3}

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What is the integral from-1 to 1 of sqrt(x) ?
The integral from-1 to 1 of sqrt(x) is 2/3+i 2/3