What is the integral from 1 to 4 of 3/(sqrt(x)) ?

The integral from 1 to 4 of 3/(sqrt(x)) is 6

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integral from 1 to 4 of 3/(sqrt(x))

\int_{1}^{4} \frac{3}{x} d x

6

Solution steps

\int_{1}^{4} \frac{3}{x} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 \cdot \int_{1}^{4} \frac{1}{x} d x

Apply the Power Rule

: [2 x^{\frac{1}{2}}]_{1}^{4}

= 3 [2 x^{\frac{1}{2}}]_{1}^{4}

Apply radical rule:

= 3 [2 x]_{1}^{4}

Compute the boundaries:

2

= 3 \cdot 2

Simplify

= 6

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What is the integral from 1 to 4 of 3/(sqrt(x)) ?
The integral from 1 to 4 of 3/(sqrt(x)) is 6