What is the integral from 1 to 5 of (6/x) ?

The integral from 1 to 5 of (6/x) is 6ln(5)

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integral from 1 to 5 of (6/x)

\int_{1}^{5} (\frac{6}{x}) d x

6 ln (5)

Decimal Notation

9.65662 \dots

Solution steps

\int_{1}^{5} \frac{6}{x} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 6 \cdot \int_{1}^{5} \frac{1}{x} d x

Use the common integral:

\int \frac{1}{x} d x = ln (∣ x ∣)

= 6 [ln ∣ x ∣]_{1}^{5}

Compute the boundaries:

ln (5)

= 6 ln (5)

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\int_{- 2}^{1} π d x

\int_{- 2}^{- 1} \frac{x ^{2} - 1}{x} d x

What is the integral from 1 to 5 of (6/x) ?
The integral from 1 to 5 of (6/x) is 6ln(5)