What is the integral from 0 to 2pi of 8/3 ?

The integral from 0 to 2pi of 8/3 is (16pi)/3

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integral from 0 to 2pi of 8/3

\int_{0}^{2 π} \frac{8}{3} d θ

\frac{16 π}{3}

Decimal Notation

16.75516 \dots

Solution steps

\int_{0}^{2 π} \frac{8}{3} d θ

Integral of a constant:

\int a d x = a x

= [\frac{8}{3} θ]_{0}^{2 π}

Compute the boundaries:

\frac{16 π}{3}

= \frac{16 π}{3}

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What is the integral from 0 to 2pi of 8/3 ?
The integral from 0 to 2pi of 8/3 is (16pi)/3