What is the integral from 1 to 0 of x^3 ?

The integral from 1 to 0 of x^3 is -1/4

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integral from 1 to 0 of x^3

\int_{1}^{0} x^{3} d x

- \frac{1}{4}

Decimal

- 0.25

Solution steps

\int_{1}^{0} x^{3} d x

\int_{a}^{b} f (x) d x = - \int_{b}^{a} f (x) d x, a < b

= - \int_{0}^{1} x^{3} d x

Apply the Power Rule

: [\frac{x ^{4}}{4}]_{0}^{1}

= - [\frac{x ^{4}}{4}]_{0}^{1}

Compute the boundaries:

\frac{1}{4}

= - \frac{1}{4}

\int_{0}^{2} 2 x x^{2} - 3 x + 2 d x

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What is the integral from 1 to 0 of x^3 ?
The integral from 1 to 0 of x^3 is -1/4