What is the integral from 0 to z of z ?

The integral from 0 to z of z is (z^2)/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to z of z

\int_{0}^{z} z d z

\frac{z ^{2}}{2}

Solution steps

\int_{0}^{z} z d z

Apply the Power Rule

: [\frac{z ^{2}}{2}]_{0}^{z}

= [\frac{z ^{2}}{2}]_{0}^{z}

Compute the boundaries:

\frac{z ^{2}}{2}

= \frac{z ^{2}}{2}

\int_{1}^{x} 2 - \frac{2 x - 2 ln ( x )}{x} d x

\int_{1}^{3} \frac{3}{x ^{3}} d x

\int_{1}^{2} x (x^{2} - 1)^{7} d x

\int_{3}^{5} 5 x d x

\int_{0}^{1} t cos (π t) d t

What is the integral from 0 to z of z ?
The integral from 0 to z of z is (z^2)/2