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Popular >

integral from 0 to 9 of (9-x)

Solution

\int_{0}^{9} (9 - x) d x

Solution

\frac{81}{2}

+1

Decimal Notation

40.5

Solution steps

\int_{0}^{9} 9 - x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{9} 9 d x - \int_{0}^{9} x d x

\int_{0}^{9} 9 d x = 81

\int_{0}^{9} x d x = \frac{81}{2}

= 81 - \frac{81}{2}

Simplify

81 - \frac{81}{2} : \frac{81}{2}

= \frac{81}{2}

Popular Examples

integral from 0 to x^2 of xcos(y)

\int_{0}^{x^{2}} x cos (y) d y

integral from 1 to 2 of 1/(1+x^2)

\int_{1}^{2} \frac{1}{1 + x ^{2}} d x

integral from 1 to 8 of 5

\int_{1}^{8} 5 d x

integral from-2 to 1 of (1/(x^2)+2)

\int_{- 2}^{1} (\frac{1}{x ^{2}} + 2) d x

integral from pi to 0 of cos(x)

\int_{π}^{0} cos (x) d x

Frequently Asked Questions (FAQ)

What is the integral from 0 to 9 of (9-x) ?
The integral from 0 to 9 of (9-x) is 81/2