What is the integral from 0 to 14pi of sin(x) ?

The integral from 0 to 14pi of sin(x) is 0

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integral from 0 to 14pi of sin(x)

\int_{0}^{14 π} sin (x) d x

0

Solution steps

\int_{0}^{14 π} sin (x) d x

Use the common integral:

\int sin (x) d x = - cos (x)

= [- cos (x)]_{0}^{14 π}

Compute the boundaries:

0

= 0

\int_{0}^{\frac{1}{4}} \frac{4}{1 + 16 x ^{2}} d x

\int_{0}^{y} e^{x^{4}} d x

\int_{- 1}^{1} (2 x^{2} - 4 x + 3) d x

\int_{2 y}^{2} cos (x^{2}) d x

\int_{0}^{3} (5 x + 2) d x

What is the integral from 0 to 14pi of sin(x) ?
The integral from 0 to 14pi of sin(x) is 0