What is the integral from 1 to 4 of x^{-1} ?

The integral from 1 to 4 of x^{-1} is 2ln(2)

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integral from 1 to 4 of x^{-1}

\int_{1}^{4} x^{- 1} d x

2 ln (2)

Decimal

1.38629 \dots

Solution steps

\int_{1}^{4} x^{- 1} d x

Use the common integral:

\int x^{- 1} d x = ln (∣ x ∣)

= [ln ∣ x ∣]_{1}^{4}

Compute the boundaries:

2 ln (2)

= 2 ln (2)

\int_{1}^{3} \frac{4 ( ln ( x ) ) ^{3}}{x} d x

\int_{2}^{1} 1 x^{5} d x

\int_{1}^{5} (\frac{1}{2 x - 1}) d x

\int_{0}^{x} ln (1 + t^{3}) d t

\int_{0}^{2} \frac{1}{1 + 2 x} d x

What is the integral from 1 to 4 of x^{-1} ?
The integral from 1 to 4 of x^{-1} is 2ln(2)