What is the integral from e to e^2 of 1/x ?

The integral from e to e^2 of 1/x is 1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from e to e^2 of 1/x

\int_{e}^{e^{2}} \frac{1}{x} d x

1

Solution steps

\int_{e}^{e^{2}} \frac{1}{x} d x

Use the common integral:

\int \frac{1}{x} d x = ln (∣ x ∣)

= [ln ∣ x ∣]_{e}^{e^{2}}

Compute the boundaries:

1

= 1

\int_{0}^{l o g_{2} (5)} 2^{x} d x

\int_{0}^{3} 3 - \frac{1}{3} x^{2} d x

\int_{2}^{4} x e^{4 x} d x

\int_{2}^{3} (x + 2)^{3} d x

\int_{0}^{60} 6 - 6 e^{- 0.11 x} d x

What is the integral from e to e^2 of 1/x ?
The integral from e to e^2 of 1/x is 1