What is the integral from 0 to 4 of cos(x^2) ?

The integral from 0 to 4 of cos(x^2) is sqrt(pi/2)\C(sqrt(2/pi)*4)-sqrt(pi/2)\C(sqrt(2/pi)*0)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to 4 of cos(x^2)

\int_{0}^{4} cos (x^{2}) d x

\frac{π}{2} C (\frac{2}{π} \cdot 4) - \frac{π}{2} C (\frac{2}{π} \cdot 0)

Solution steps

\int_{0}^{4} cos (x^{2}) d x

Use the nonelementary integral:

\int cos (x^{2}) d x = \frac{π}{2} C (\frac{2}{π} x)

= [\frac{π}{2} C (\frac{2}{π} x)]_{0}^{4}

Compute the boundaries:

\frac{π}{2} C (\frac{2}{π} \cdot 4) - \frac{π}{2} C (\frac{2}{π} \cdot 0)

= \frac{π}{2} C (\frac{2}{π} \cdot 4) - \frac{π}{2} C (\frac{2}{π} \cdot 0)

\int_{1}^{2} (x + \frac{2}{x})^{2} d x

\int_{0}^{2} 6 x - 3 x^{2} d x

\int_{l n (0.5)}^{0} e^{x} d x

\int_{- 4}^{2} x d x

\int_{- 1}^{3} 3 d x

What is the integral from 0 to 4 of cos(x^2) ?
The integral from 0 to 4 of cos(x^2) is sqrt(pi/2)\C(sqrt(2/pi)*4)-sqrt(pi/2)\C(sqrt(2/pi)*0)