What is the integral from-pi/4 to pi/4 of (sec^2(x)) ?

The integral from-pi/4 to pi/4 of (sec^2(x)) is 2

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integral from-pi/4 to pi/4 of (sec^2(x))

\int_{- \frac{π}{4}}^{\frac{π}{4}} (sec^{2} (x)) d x

2

Solution steps

\int_{- \frac{π}{4}}^{\frac{π}{4}} sec^{2} (x) d x

Use the common integral:

\int sec^{2} (x) d x = tan (x)

= [tan (x)]_{- \frac{π}{4}}^{\frac{π}{4}}

Compute the boundaries:

2

= 2

\int_{0}^{1} e^{x^{3}} x^{2} d x

\int_{- 1}^{5} 2 x + 4 d x

\int_{0}^{1} x^{2} + x - 2 d x

\int_{0}^{x} \frac{t}{2} d t

\int_{0}^{2} (t i + e^{t} j - t e^{t} k) d t

What is the integral from-pi/4 to pi/4 of (sec^2(x)) ?
The integral from-pi/4 to pi/4 of (sec^2(x)) is 2