What is the integral from 0 to-pi of cos(x) ?

The integral from 0 to-pi of cos(x) is 0

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integral from 0 to-pi of cos(x)

\int_{0}^{- π} cos (x) d x

0

Solution steps

\int_{0}^{- π} cos (x) d x

\int_{a}^{b} f (x) d x = - \int_{b}^{a} f (x) d x, a < b

= - \int_{- π}^{0} cos (x) d x

Use the common integral:

\int cos (x) d x = sin (x)

= - [sin (x)]_{- π}^{0}

Compute the boundaries:

0

= - 0

Simplify

= 0

\int_{0}^{y} \frac{6 ( y - x )}{125} d x

\int_{- 1}^{2} 5 - x^{2} d x

\int_{- 1}^{1} (arccos (x))^{2} d x

\int_{1}^{3} \frac{1}{t} d t

\int_{0}^{1} - t^{2} d t

What is the integral from 0 to-pi of cos(x) ?
The integral from 0 to-pi of cos(x) is 0