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Popular >

integral from 0 to 4 of |x^2-4|

Solution

\int_{0}^{4} x^{2} - 4 d x

Solution

16

Solution steps

\int_{0}^{4} x^{2} - 4 d x

Eliminate Absolutes

= \int_{0}^{2} - x^{2} + 4 d x + \int_{2}^{4} x^{2} - 4 d x

\int_{0}^{2} - x^{2} + 4 d x = \frac{16}{3}

\int_{2}^{4} x^{2} - 4 d x = \frac{32}{3}

= \frac{16}{3} + \frac{32}{3}

Simplify

\frac{16}{3} + \frac{32}{3} : 16

= 16

Graph

Popular Examples

integral from 1 to 2 of (v^4+4v^8)/(v^5)

\int_{1}^{2} \frac{v ^{4} + 4 v ^{8}}{v ^{5}} d v

integral from 2 to 4 of ln(x+1)

\int_{2}^{4} ln (x + 1) d x

integral from-1 to 0 of 1/(x^2+2x+2)

\int_{- 1}^{0} \frac{1}{x ^{2} + 2 x + 2} d x

integral from 1 to 3 of 1/(sqrt(4x-x^2))

\int_{1}^{3} \frac{1}{4 x - x ^{2}} d x

integral from 0 to pi/2 of |sin(x)|

\int_{0}^{\frac{π}{2}} ∣ sin (x) ∣ d x

Frequently Asked Questions (FAQ)

What is the integral from 0 to 4 of |x^2-4| ?
The integral from 0 to 4 of |x^2-4| is 16