What is the integral from 0 to pi/2 of 8cos(x) ?

The integral from 0 to pi/2 of 8cos(x) is 8

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to pi/2 of 8cos(x)

\int_{0}^{\frac{π}{2}} 8 cos (x) d x

8

Solution steps

\int_{0}^{\frac{π}{2}} 8 cos (x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 8 \cdot \int_{0}^{\frac{π}{2}} cos (x) d x

Use the common integral:

\int cos (x) d x = sin (x)

= 8 [sin (x)]_{0}^{\frac{π}{2}}

Compute the boundaries:

1

= 8 \cdot 1

Simplify

= 8

\int_{- 3}^{3} ∣ x + 1 ∣ d x

\int_{0}^{1} 5 x^{3} d x

\int_{1}^{4} (\frac{3}{x}) d x

\int_{0}^{1} x^{2} 1 - x d x

\int_{1}^{2} \frac{2 x + 1}{12} d x

What is the integral from 0 to pi/2 of 8cos(x) ?
The integral from 0 to pi/2 of 8cos(x) is 8