What is the integral from 0 to 1 of xcos((pix)/2) ?

The integral from 0 to 1 of xcos((pix)/2) is (2(pi-2))/(pi^2)

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integral from 0 to 1 of xcos((pix)/2)

\int_{0}^{1} x cos (\frac{π x}{2}) d x

\frac{2 ( π - 2 )}{π ^{2}}

Decimal

0.23133 \dots

Solution steps

\int_{0}^{1} x cos (\frac{π x}{2}) d x

Apply u-substitution

: \int_{0}^{\frac{π}{2}} \frac{4 u cos ( u )}{π ^{2}} d u

= \int_{0}^{\frac{π}{2}} \frac{4 u cos ( u )}{π ^{2}} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{4}{π ^{2}} \cdot \int_{0}^{\frac{π}{2}} u cos (u) d u

Apply Integration By Parts

: [u sin (u) - \int sin (u) d u]_{0}^{\frac{π}{2}}

= \frac{4}{π ^{2}} [u sin (u) - \int sin (u) d u]_{0}^{\frac{π}{2}}

\int sin (u) d u = - cos (u)

= \frac{4}{π ^{2}} [u sin (u) - (- cos (u))]_{0}^{\frac{π}{2}}

Simplify

= \frac{4}{π ^{2}} [u sin (u) + cos (u)]_{0}^{\frac{π}{2}}

Compute the boundaries:

\frac{π}{2} - 1

= \frac{4}{π ^{2}} (\frac{π}{2} - 1)

Simplify

= \frac{2 ( π - 2 )}{π ^{2}}

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\int_{1}^{e} \frac{1}{x ^{2}} d x

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What is the integral from 0 to 1 of xcos((pix)/2) ?
The integral from 0 to 1 of xcos((pix)/2) is (2(pi-2))/(pi^2)