What is the integral from-2 to-1 of 1/((x+1)^2) ?

The integral from-2 to-1 of 1/((x+1)^2) is diverges

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integral from-2 to-1 of 1/((x+1)^2)

\int_{- 2}^{- 1} \frac{1}{( x + 1 ) ^{2}} d x

diverges

Solution steps

\int_{- 2}^{- 1} \frac{1}{( x + 1 ) ^{2}} d x

Apply u-substitution

: \int_{- 1}^{0} \frac{1}{u ^{2}} d u

= \int_{- 1}^{0} \frac{1}{u ^{2}} d u

Apply the Power Rule

: [- \frac{1}{u}]_{- 1}^{0}

= [- \frac{1}{u}]_{- 1}^{0}

Compute the boundaries:

diverges

= diverges

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What is the integral from-2 to-1 of 1/((x+1)^2) ?
The integral from-2 to-1 of 1/((x+1)^2) is diverges