What is the integral from 0 to 1 of 3/8 x^2 ?

The integral from 0 to 1 of 3/8 x^2 is 1/8

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integral from 0 to 1 of 3/8 x^2

\int_{0}^{1} \frac{3}{8} x^{2} d x

\frac{1}{8}

Decimal

0.125

Solution steps

\int_{0}^{1} \frac{3}{8} x^{2} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{3}{8} \cdot \int_{0}^{1} x^{2} d x

Apply the Power Rule

: [\frac{x ^{3}}{3}]_{0}^{1}

= \frac{3}{8} [\frac{x ^{3}}{3}]_{0}^{1}

Compute the boundaries:

\frac{1}{3}

= \frac{3}{8} \cdot \frac{1}{3}

Simplify

= \frac{1}{8}

\int_{0}^{3} 2 x + 1 - 2 d x

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\int_{- 3}^{0} \frac{1}{x + 3} d x

What is the integral from 0 to 1 of 3/8 x^2 ?
The integral from 0 to 1 of 3/8 x^2 is 1/8