What is the integral from 1 to 6 of (1+2x^3) ?

The integral from 1 to 6 of (1+2x^3) is 1305/2

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integral from 1 to 6 of (1+2x^3)

\int_{1}^{6} (1 + 2 x^{3}) d x

\frac{1305}{2}

Decimal

652.5

Solution steps

\int_{1}^{6} 1 + 2 x^{3} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{6} 1 d x + \int_{1}^{6} 2 x^{3} d x

\int_{1}^{6} 1 d x = 5

\int_{1}^{6} 2 x^{3} d x = \frac{1295}{2}

= 5 + \frac{1295}{2}

Simplify

5 + \frac{1295}{2} : \frac{1305}{2}

= \frac{1305}{2}

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What is the integral from 1 to 6 of (1+2x^3) ?
The integral from 1 to 6 of (1+2x^3) is 1305/2