What is the integral from 0 to log_{2 of (3)}2^x ?

The integral from 0 to log_{2 of (3)}2^x is 2/(ln(2))

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integral from 0 to log_{2 of (3)}2^x

\int_{0}^{l o g_{2} (3)} 2^{x} d x

\frac{2}{ln ( 2 )}

Decimal

2.88539 \dots

Solution steps

\int_{0}^{l o g_{2} (3)} 2^{x} d x

\int a^{x} d x = \frac{a ^{x}}{ln a}

= [\frac{2 ^{x}}{ln ( 2 )}]_{0}^{l o g_{2} (3)}

Compute the boundaries:

\frac{2}{ln ( 2 )}

= \frac{2}{ln ( 2 )}

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What is the integral from 0 to log_{2 of (3)}2^x ?
The integral from 0 to log_{2 of (3)}2^x is 2/(ln(2))