What is the integral from 0 to a of e^{-t^2} ?

The integral from 0 to a of e^{-t^2} is (sqrt(pi))/2 \erf(a)

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integral from 0 to a of e^{-t^2}

\int_{0}^{a} e^{- t^{2}} d t

\frac{π}{2} erf (a)

Solution steps

\int_{0}^{a} e^{- t^{2}} d t

Use the nonelementary integral:

\int e^{- t^{2}} d t = \frac{π}{2} erf (t)

= [\frac{π}{2} erf (t)]_{0}^{a}

Compute the boundaries:

\frac{π}{2} erf (a)

= \frac{π}{2} erf (a)

\int_{0}^{0.2} e^{- x^{2}} d x

\int_{1}^{2} x + 2 d x

\int_{- 6}^{6} 1

\int_{0}^{\frac{1}{y}} y e^{x y} d x

\int_{- 5}^{5} 1 d x

What is the integral from 0 to a of e^{-t^2} ?
The integral from 0 to a of e^{-t^2} is (sqrt(pi))/2 \erf(a)