What is the integral from 0 to 2 of 6x^3 ?

The integral from 0 to 2 of 6x^3 is 24

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to 2 of 6x^3

\int_{0}^{2} 6 x^{3} d x

24

Solution steps

\int_{0}^{2} 6 x^{3} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 6 \cdot \int_{0}^{2} x^{3} d x

Apply the Power Rule

: [\frac{x ^{4}}{4}]_{0}^{2}

= 6 [\frac{x ^{4}}{4}]_{0}^{2}

Compute the boundaries:

4

= 6 \cdot 4

Simplify

= 24

\int_{2}^{3} x^{2} - 2 x d x

\int_{- 2}^{2} - x d x

\int_{- 3}^{1} 3 - 2 x - x^{2} d x

\int_{2}^{4} ∣ x - 3 ∣ d x

\int_{- 1}^{2} 4 x^{2} d x

What is the integral from 0 to 2 of 6x^3 ?
The integral from 0 to 2 of 6x^3 is 24