What is the integral from 1 to infinity of 1/(x^n) ?

The integral from 1 to infinity of 1/(x^n) is Undefined-1/(-n+1)

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integral from 1 to infinity of 1/(x^n)

\int_{1}^{\infty} \frac{1}{x ^{n}} d x

Undefined - \frac{1}{- n + 1}

Solution steps

\int_{1}^{\infty} \frac{1}{x ^{n}} d x

Compute the indefinite integral:

\int \frac{1}{x ^{n}} d x = \frac{x ^{- n + 1}}{- n + 1} + C

Compute the boundaries:

\int_{1}^{\infty} \frac{1}{x ^{n}} d x =

Undefined

- \frac{1}{- n + 1}

= Undefined - \frac{1}{- n + 1}

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What is the integral from 1 to infinity of 1/(x^n) ?
The integral from 1 to infinity of 1/(x^n) is Undefined-1/(-n+1)