What is the integral from 0 to 7 of x^3 ?

The integral from 0 to 7 of x^3 is 2401/4

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integral from 0 to 7 of x^3

\int_{0}^{7} x^{3} d x

\frac{2401}{4}

Decimal

600.25

Solution steps

\int_{0}^{7} x^{3} d x

Apply the Power Rule

: [\frac{x ^{4}}{4}]_{0}^{7}

= [\frac{x ^{4}}{4}]_{0}^{7}

Compute the boundaries:

\frac{2401}{4}

= \frac{2401}{4}

\int_{0}^{2} (2 x - x^{2} + 1) d x

\int_{1}^{10} \frac{2}{x} d x

\int_{0}^{1} ∣ 1 - 2 x ∣ d x

\int_{1}^{2} (3 t^{2} + 2 e^{3 t} + \frac{1}{t} + 2 cos (3 t)) d t

\int_{b}^{a} 1 d x

What is the integral from 0 to 7 of x^3 ?
The integral from 0 to 7 of x^3 is 2401/4