What is the integral from-infinity to 5 of θe^θ ?

The integral from-infinity to 5 of θe^θ is 4e^5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from-infinity to 5 of θe^θ

\int_{- \infty}^{5} θ e^{θ} d θ

4 e^{5}

Decimal

593.65263 \dots

Solution steps

\int_{- \infty}^{5} θ e^{θ} d θ

Compute the indefinite integral:

\int θ e^{θ} d θ = e^{θ} θ - e^{θ} + C

Compute the boundaries:

\int_{- \infty}^{5} θ e^{θ} d θ = 4 e^{5} - 0

= 4 e^{5} - 0

Simplify

= 4 e^{5}

\int_{3}^{x} 9 - y^{2} d y

\int_{0}^{6} 3 d x

\int_{\frac{1}{2}}^{4} x^{3} - 6 x^{2} + 9 x + 1 d x

\int_{- 2}^{2} e^{u + 2} d u

\int_{0}^{x} 16 - t^{2} d t

What is the integral from-infinity to 5 of θe^θ ?
The integral from-infinity to 5 of θe^θ is 4e^5