What is the integral from-3 to 3 of (sin(x))/(1+x^2) ?

The integral from-3 to 3 of (sin(x))/(1+x^2) is 0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from-3 to 3 of (sin(x))/(1+x^2)

\int_{- 3}^{3} \frac{sin ( x )}{1 + x ^{2}} d x

0

Solution steps

\int_{- 3}^{3} \frac{sin ( x )}{1 + x ^{2}} d x

If f(x) is an odd function and continuous at:

[- a, a]

then

\int_{- a}^{a} f (x) d x = 0

Parity of

\frac{sin ( x )}{1 + x ^{2}} :

Odd

= 0

\int_{0}^{2} \frac{1}{e ^{\frac{x}{2}} + e ^{x}} d x

\int_{1}^{\infty} 5 x^{- 6} d x

\int_{0}^{4} 5 x^{2} + x d x

\int_{1}^{3} 3 x^{2} - 6 x + 2 d x

\int_{0}^{1} x^{2} (1 - x^{2}) d x

What is the integral from-3 to 3 of (sin(x))/(1+x^2) ?
The integral from-3 to 3 of (sin(x))/(1+x^2) is 0