What is the integral from 1 to 6 of (3/x) ?

The integral from 1 to 6 of (3/x) is 3ln(6)

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integral from 1 to 6 of (3/x)

\int_{1}^{6} (\frac{3}{x}) d x

3 ln (6)

Decimal

5.37527 \dots

Solution steps

\int_{1}^{6} \frac{3}{x} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 \cdot \int_{1}^{6} \frac{1}{x} d x

Use the common integral:

\int \frac{1}{x} d x = ln (∣ x ∣)

= 3 [ln ∣ x ∣]_{1}^{6}

Compute the boundaries:

ln (6)

= 3 ln (6)

\int_{- 1}^{1} 4 - x^{2} d x

\int_{0}^{60} 3 - 3 e^{- 0.15 t} d t

\int_{2}^{4} (6 x^{2} - 6 x - 1) d x

\int_{- 1}^{2} (1 - x^{2}) x d x

\int_{0}^{1} t e^{\frac{t ^{2}}{2}} d t

What is the integral from 1 to 6 of (3/x) ?
The integral from 1 to 6 of (3/x) is 3ln(6)