What is the integral from-infinity to 1 of e^{2x} ?

The integral from-infinity to 1 of e^{2x} is (e^2)/2

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integral from-infinity to 1 of e^{2x}

\int_{- \infty}^{1} e^{2 x} d x

\frac{e ^{2}}{2}

Decimal

3.69452 \dots

Solution steps

\int_{- \infty}^{1} e^{2 x} d x

Compute the indefinite integral:

\int e^{2 x} d x = \frac{1}{2} e^{2 x} + C

Compute the boundaries:

\int_{- \infty}^{1} e^{2 x} d x = \frac{e ^{2}}{2} - 0

= \frac{e ^{2}}{2} - 0

Simplify

= \frac{e ^{2}}{2}

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What is the integral from-infinity to 1 of e^{2x} ?
The integral from-infinity to 1 of e^{2x} is (e^2)/2