What is the integral from 0 to 1 of sqrt(4+5x) ?

The integral from 0 to 1 of sqrt(4+5x) is 38/15

Popular >

integral from 0 to 1 of sqrt(4+5x)

\int_{0}^{1} 4 + 5 x d x

\frac{38}{15}

Decimal

2.53333 \dots

Solution steps

\int_{0}^{1} 4 + 5 x d x

Apply u-substitution

: \int_{4}^{9} \frac{u}{5} d u

= \int_{4}^{9} \frac{u}{5} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{5} \cdot \int_{4}^{9} u d u

Apply the Power Rule

: [\frac{2}{3} u^{\frac{3}{2}}]_{4}^{9}

= \frac{1}{5} [\frac{2}{3} u^{\frac{3}{2}}]_{4}^{9}

Compute the boundaries:

\frac{38}{3}

= \frac{1}{5} \cdot \frac{38}{3}

Simplify

= \frac{38}{15}

\int_{- 4}^{3} (- x^{2} - x + 12) d x

\int_{0}^{8} (64 - x^{2}) d x

\int_{x}^{x} \frac{e ^{t}}{t} d t

\int_{- 1}^{1} y^{2} - 2 d y

\int_{0}^{1} \frac{8}{x ^{2} + 1} d x

What is the integral from 0 to 1 of sqrt(4+5x) ?
The integral from 0 to 1 of sqrt(4+5x) is 38/15