What is the integral from 0 to 1 of (-1) ?

The integral from 0 to 1 of (-1) is -1

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integral from 0 to 1 of (-1)

\int_{0}^{1} (- 1) d x

- 1

Solution steps

\int_{0}^{1} - 1 d x

Integral of a constant:

\int a d x = a x

= [(- 1) x]_{0}^{1}

Simplify

= [- x]_{0}^{1}

Compute the boundaries:

- 1

= - 1

\int_{0}^{1} π (x^{4} - x^{2}) d x

\int_{0}^{\frac{π}{2}} e^{x} sin^{2} (x) d x

\int_{0}^{2} 3 x 4 - x^{2} d x

\int_{- 11}^{1} x 5 - x d x

\int_{0}^{2} - x^{4} + 2 x^{2} + 8 d x

What is the integral from 0 to 1 of (-1) ?
The integral from 0 to 1 of (-1) is -1