What is the integral from 1 to 3 of (3/(x^2)) ?

The integral from 1 to 3 of (3/(x^2)) is 2

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integral from 1 to 3 of (3/(x^2))

\int_{1}^{3} (\frac{3}{x ^{2}}) d x

2

Solution steps

\int_{1}^{3} \frac{3}{x ^{2}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 \cdot \int_{1}^{3} \frac{1}{x ^{2}} d x

Apply the Power Rule

: [- \frac{1}{x}]_{1}^{3}

= 3 [- \frac{1}{x}]_{1}^{3}

Compute the boundaries:

\frac{2}{3}

= 3 \cdot \frac{2}{3}

Simplify

= 2

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\int_{- 1}^{1} (x^{3} + 1) d x

\int_{2}^{3} \frac{1}{x ^{3}} d x

\int_{- \frac{π}{2}}^{\frac{π}{2}} sin (θ) d θ

What is the integral from 1 to 3 of (3/(x^2)) ?
The integral from 1 to 3 of (3/(x^2)) is 2