What is the integral from 2 to 3 of 1/((x-1)^3) ?

The integral from 2 to 3 of 1/((x-1)^3) is 3/8

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 2 to 3 of 1/((x-1)^3)

\int_{2}^{3} \frac{1}{( x - 1 ) ^{3}} d x

\frac{3}{8}

Decimal

0.375

Solution steps

\int_{2}^{3} \frac{1}{( x - 1 ) ^{3}} d x

Apply u-substitution

: \int_{1}^{2} \frac{1}{u ^{3}} d u

= \int_{1}^{2} \frac{1}{u ^{3}} d u

Apply the Power Rule

: [- \frac{1}{2 u ^{2}}]_{1}^{2}

= [- \frac{1}{2 u ^{2}}]_{1}^{2}

Compute the boundaries:

\frac{3}{8}

= \frac{3}{8}

\int_{- 8}^{8} 3 x^{4} d x

\int_{0}^{4} (4 - 4 x) - (4 - x^{2}) d x

\int_{0}^{3} \frac{1}{x ^{2} + 9} d x

\int_{1}^{2} x^{2} e^{x^{3}} d x

\int_{0}^{2} x (2 x^{2} - 5) d x

What is the integral from 2 to 3 of 1/((x-1)^3) ?
The integral from 2 to 3 of 1/((x-1)^3) is 3/8