What is the integral from-1 to e-2 of 1/(x+2) ?

The integral from-1 to e-2 of 1/(x+2) is 1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from-1 to e-2 of 1/(x+2)

\int_{- 1}^{e - 2} \frac{1}{x + 2} d x

1

Solution steps

\int_{- 1}^{e - 2} \frac{1}{x + 2} d x

Apply u-substitution

: \int_{1}^{e} \frac{1}{u} d u

= \int_{1}^{e} \frac{1}{u} d u

Use the common integral:

\int \frac{1}{u} d u = ln (∣ u ∣)

= [ln ∣ u ∣]_{1}^{e}

Compute the boundaries:

1

= 1

\int_{0}^{2} (x^{3} - 2 x + e^{x}) d x

\int_{0}^{2} (2) d x

\int_{0}^{1} 6 x e^{x} d x

\int_{0}^{40} q^{2} + 10 q - 90 d q

\int_{0}^{a} r a^{2} - r^{2} d r

What is the integral from-1 to e-2 of 1/(x+2) ?
The integral from-1 to e-2 of 1/(x+2) is 1