What is the integral from 0 to 5 of (x^2) ?

The integral from 0 to 5 of (x^2) is 125/3

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integral from 0 to 5 of (x^2)

\int_{0}^{5} (x^{2}) d x

\frac{125}{3}

Decimal

41.66666 \dots

Solution steps

\int_{0}^{5} x^{2} d x

Apply the Power Rule

: [\frac{x ^{3}}{3}]_{0}^{5}

= [\frac{x ^{3}}{3}]_{0}^{5}

Compute the boundaries:

\frac{125}{3}

= \frac{125}{3}

\int_{0}^{1} 5^{5 x} d x

\int_{0}^{\frac{π}{2}} cos (\frac{x}{3}) d x

\int_{- \frac{π}{2}}^{\frac{π}{2}} 2 sin (x) d x

\int_{1}^{e} (4 e^{x} + 4 sin (x)) d x

\int_{- \frac{π}{4}}^{\frac{π}{4}} csc^{2} (x) d x

What is the integral from 0 to 5 of (x^2) ?
The integral from 0 to 5 of (x^2) is 125/3