What is the integral from 0 to y of 6y ?

The integral from 0 to y of 6y is 3y^2

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integral from 0 to y of 6y

\int_{0}^{y} 6 y d y

3 y^{2}

Solution steps

\int_{0}^{y} 6 y d y

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 6 \cdot \int_{0}^{y} y d y

Apply the Power Rule

: [\frac{y ^{2}}{2}]_{0}^{y}

= 6 [\frac{y ^{2}}{2}]_{0}^{y}

Compute the boundaries:

\frac{y ^{2}}{2}

= 6 \cdot \frac{y ^{2}}{2}

Simplify

= 3 y^{2}

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