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Popular >

integral from-2 to 1 of (1+2y^2)

Solution

\int_{- 2}^{1} (1 + 2 y^{2}) d y

Solution

9

Solution steps

\int_{- 2}^{1} 1 + 2 y^{2} d y

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 2}^{1} 1 d y + \int_{- 2}^{1} 2 y^{2} d y

\int_{- 2}^{1} 1 d y = 3

\int_{- 2}^{1} 2 y^{2} d y = 6

= 3 + 6

Simplify

= 9

Graph

Popular Examples

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\int_{1}^{2} \frac{1}{x + x ^{3}} d x

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\int_{1}^{e} \frac{5 ln ( x )}{x} d x

integral from 0 to 2 of 2x(x^2+4)^2

\int_{0}^{2} 2 x (x^{2} + 4)^{2} d x

integral from 1 to 4 of (-x+4/x)

\int_{1}^{4} (- x + \frac{4}{x}) d x

integral from 1 to 10 of 5/x

\int_{1}^{10} \frac{5}{x} d x

Frequently Asked Questions (FAQ)

What is the integral from-2 to 1 of (1+2y^2) ?
The integral from-2 to 1 of (1+2y^2) is 9